OK - this is more homework for you, so I'm not giving you the answers fully - you'll have to do some thinking for yourself.
How big a volume would you expect to have for a PCR (for 1 tube)? - so what sort of volume would you be pipetting for the primers (ml? l? ul? nl?)?
uM is micro mol per litre, how many pmol of primers will be in each reaction? And what volume would that work out to be?
Serial dilutions - you could do 1:10 dilution or any other multiple to get it to a pipettable volume (0.5 ul and above). 1:10 and 1:2 are the easiest as they are kind of intuitive (multiply by 10 or 2 respectively)
For dilutions the best equation to use is Vi x Ci = Vf x Cf where V and C are volume and concentration and i and f are initial and final respectively.
The volume for PCR will be in the microlitres. We'll be using 25ul total reaction.
0.3uM = 0.3pico mol / ul. Does this mean that from my stock of 10uM, pipetting 1ul will give me 0.3pico mol for my reaction tube?
I normally do use civ1 =c2v2 in calculations but here there is no given vf (as I'm designing the experiment and I just know it should be below 2ul)
For the serial dilution. If I multiply by 10 I can reach a pipettable amount. So from 0.056/1, multiplied by 10 I get 0.56/10 dilution.I can pipet this by adding 0.56ul in 10(-0.56)ul. From this do I add 1ul to my final tube?
Sorry if it's all over the place, I am a confused about this topic.