0,2uM is 100ng of a 18-mer primer - (Jul/18/2006 )

I wonder how they can calculate that 100ng of a 18-mer primer is about 0,2uM. Do they use any tools or how do they know it?


Thanks.

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it seems there is a little mistake here. you have forgotten /mL I guess.
if you know the average molecular weight of a mer (I don't), you can calculate the molarity of a 18-mer if you know the concentration (ng/mL)

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Dear Missele,

Thanks for replying. Yes, it should be 100ng/ul. A DNA base weights approx. 300-330 daltons. Can you show me how i can calculate the molarity of a 18-mer? This is quite hard for me. I do not know how to make daltons into molarity.

Thanks again!

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1 dalton is 1 g/mol

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hmm, I have a head ache, and I can't find the right result !

1 base is 330 dalton, it means 330g/mol. from 330g you get 1 mol
For a 18-mer, it's quite 18 times : 1 mole is 330*18=5940g

you have 100 ng/µL

100 g is 100/5940=0.016 mol
100 ng is 0.016 nmol
100 ng/µL is 0.016 nmol/µL, or 0.016mmol/L (id est 0.016 mM)


Where is my mistake?

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I do not know. does anyone has any suggestions? 0.016mM is the same as 16uM. It should be 0.2uM.

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I completely agree with Missele. That's the right way of calculating the molarity.

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I would say it's 0,2 µM:

(100 E-9 g/µl) / 5940 g/mol = 0,17 E-12 mol/µl = 0,17 E-6 mol/l = 0,17 µM ~ 0,2 µM

sorry if it's too crowded...

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U can find the use this formula to calculate.



From IDT's website: Milligrams = Molecular Weight * Nanomoles * 10-6

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