# Enzyme Units RNaseA - (Jul/25/2012 )

Hi,

I'm following a protocol which requires 20U of RNAse A to be added to a DNA extraction. I can't get my head around working out how much I need to add. The RNaseA I have is this one http://products.invitrogen.com/ivgn/product/12091021 and apparently it has an activity of not less than 70 U⁄mg material.
Searching the web all I've discovered is "1 enzyme unit (U) = 1 μmol min−1. 1 U corresponds to 16.67 nanokatals.<1>"

I'm thinking if I need 20 units absolute, I need to work that out as a concentration of my volume in microlitres, and then use C1xV1=C2xV2:

2ml of DNA+TE Buffer Solution
20U = 20/2000 = 0.01 Units per microlitre.

I'm assuming if 1ml more or less equals 1g then 1 microlitre more or less = 1 milligram.

70U/mg x V1 = 0.01U/ul x 2000

V1 = (0.01 / 70) x 2000 = 0.285ul

This may be completely wrong but I'm not sure how else to work this out.

Thanks,
Ben W.

-Axolotl9250-

this is not a c1v1=c2v2 problem. you are not looking for a final concentration. you are looking for an absolute amount.

you have a 20mg/ml solution of rnase and the specific activity is 70 units/mg (1400 units/ml). you want 20 units to put into your dna solution. 20/70=0.2857.

you, therefore, want approximately 0.29mg (20.3 units). 20mg/ml=1mg/50ul. 0.29x50=14.5ul.

or you can calculate this way:

20units/1400units/ml=0.014286ml=~14.3ul

-mdfenko-

Thanks! That's much easier than I was playing it up in my head I think.

-Axolotl9250-

But, you put  14.3ul  of RNAse independently of volume of DNA solution?, for example I have 500uL of DNA. Should I put 14.3ul? I dont understand that calculation.
Thanks a Lot

-Xavi123456-

Xavi123456 on Tue Nov 22 19:27:34 2016 said:

mdfenko

But, you put  14.3ul  of RNAse independently of volume of DNA solution?, for example I have 500uL of DNA. Should I put 14.3ul? I dont understand that calculation.
Thanks a Lot

the calculation was not to determine final concentration, it was to add a specific mass of enzyme to the solution. this will slightly dilute the sample but will deliver the specific amount of enzyme

-mdfenko-