# urgent! calculating concentration of compound with different cell amounts - (Apr/16/2012 )

Hi guys!

This might seem a stupid question, but just to be sure!

I want to test a couple of inhibitors in vitro to check expression of genes related with immune response in my cells. I know the IC50 value of these compounds from an assay with 2x10^5 cells/mL, and I have some data about previous titration of this inhibitors (using different concentrations of the inhibitors on 2x10^5 cells/mL to find what is good to inhibit my target enzymes). So, lets say that 1µM is a concentration that is good to inhibit my enzymes without finding cytotoxic effects on my cells.

Now, the thing is that I have to stimulate cells to check for immune response (with LPS, TNF) and see if my inhibitors have some effect. The protocol that I have for stimulation is for 1x10^6 cells/mL. If I would like to add my inhibitors directly to these cells on 1x10^6 cells/mL together with my stimuli, would it be valid to say:

- 1µM of inhibitor for 2x10^5 cells/mL --> for 1x10^6 cells/mL (5x more cells), then 5µM of inhibitor?

-irisgzz-

1µM for 2x10^5 cells/ml

1µM for 2x10^5 cells/ml
II
II : 2x10^5
II X 1x10^6
V
? µM for 1x10^6 cells/ml

Use simple math: for 1x10^6 cells/ml it is 1µM divided by 2x10^5 and multiplied by 1x10^6 cells/ml, which gives you: 5 µM , or indeed as you allready noticed, its 5 times more cells.. so indeed multiply by 5.

-pito-

pito on Mon Apr 16 09:13:10 2012 said:

1µM for 2x10^5 cells/ml

1µM for 2x10^5 cells/ml
II
II : 2x10^5
II X 1x10^6
V
? µM for 1x10^6 cells/ml

Thanks a lot! = )

Use simple math: for 1x10^6 cells/ml it is 1µM divided by 2x10^5 and multiplied by 1x10^6 cells/ml, which gives you: 5 µM , or indeed as you allready noticed, its 5 times more cells.. so indeed multiply by 5.

-irisgzz-

I would say that the amount of compound present in the solution at 1 uM/L is likely to be enough to work for any number of cells, so you shouldn't need to adjust it.

-bob1-