to treat cells with inhibitor - (Feb/08/2012 )

Hello everybody,

I just want to ask about some calculations about varying concentrations of drug treatments to my cells. For example, i have a 1uM stock of the drug and I need to treat the cells (3x10^3) in 3 cm dish with 100 nM in 2 ml of medium.

Does that mean i just simply dilute my drug to 100 nM from my 1uM stock and add it directly to my cells? or do i need to compute and consider the 2 ml of medium in the dish?

if you can share with me links or books to do math and computations of concentrations, i would be happy to know. thank yoou...

-soymilk14-

You have a stock of 1uM and you need 100nM. SO basically dilution factor of 10. For 2ml, 2ml/10 = 0.2ml. SO you need to add 200ul of the stock + 1800ul of media, for final concentration of 100nM.

There is the easier way below.

Go to the bottom, to dilute a stock solution. Enter the values and final volume as 2ml, and you will have the dilution factor.

-scolix-

soymilk14 on Thu Feb 9 02:53:44 2012 said:

Hello everybody,

I just want to ask about some calculations about varying concentrations of drug treatments to my cells. For example, i have a 1uM stock of the drug and I need to treat the cells (3x10^3) in 3 cm dish with 100 nM in 2 ml of medium.

Does that mean i just simply dilute my drug to 100 nM from my 1uM stock and add it directly to my cells? or do i need to compute and consider the 2 ml of medium in the dish?

if you can share with me links or books to do math and computations of concentrations, i would be happy to know. thank yoou...

Note that concentration of solutions is entirely independent of volume - whether you have 100 ul or 10000 l you will still have a solution! From your post I can't tell if you need to add exactly 100 nm to each treatment or whether you want a 100 nm/l solution - in which case Scolix has answered you problem

-bob1-