How to prepare this solution ? - (May/31/2010 )
Dear all,
I'm confusing about the preparation of a solution I should to use.
I have a solution NaCl 12% and I have to prepare 9 % in 8 ml.
How can I do ?
I don't thing the 3 basis rule (C1V1=C2V2) would work, right?
Thank you for help
-Biog-
Biog on May 31 2010, 10:29 PM said:
I don't thing the 3 basis rule (C1V1=C2V2) would work, right?
why not?
-Gerard-
Gerard on May 31 2010, 01:33 PM said:
Biog on May 31 2010, 10:29 PM said:
I don't thing the 3 basis rule (C1V1=C2V2) would work, right?
why not?
I don't know, just doubt !
Skeptical
!But definitely it could be used, no?
-Biog-
of course it can:
12%xv1=9%x8ml
v1=(9x8)/12=6ml
-mdfenko-
mdfenko on Jun 1 2010, 11:40 AM said:
of course it can:
12%xv1=9%x8ml
v1=(9x8)/12=6ml
12%xv1=9%x8ml
v1=(9x8)/12=6ml
Yes, that is right. Thank you.
-Biog-