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#114068 Newbie- choose DNA template
Posted
perneseblue
on 02 July 2011 - 05:02 AM
Do you plan to work with cDNA (without introns) or a full size gene?
Human gene tend to have splice site variant and contain regulatory elements within their introns. A cDNA will not be able to capture these facets.
On the other hand full size eukaryote tend to be very big and not easy to manipulate. cDNA tend to be much smaller.
Depending on your answer, you may use one these as a template
a plasmid from a cDNA libraries
a plasmid from a BAC libraries
raw human DNA.
So where can you get a template?
You may either purchase the template DNA or obtain it from a lab working in the field. Using pubmed find out who has publish work on your protein of interest and email them. Invitrogen and Open Biosystems are examples of places where you may purchase a BAC libraries. A google search will turn up more places which sells cDNA or BAC libraries.
Working with raw human DNA is not easy. Stick with libraries.
#130551 Cosmetic recall
Posted
Phil Geis
on 06 March 2012 - 05:30 PM
As I said, there are no data (more correctly, I' not aware of such data and I have searched for it) that living in environments such as a farm exposes one to substantially greater immunoligic stimulus - and the differecne would have to be exponential both in exposure and effect to be clinicaly significant..
#107248 Self-circularization-How to prevent other unwanted ligations
Posted
phage434
on 19 April 2011 - 10:13 AM
So, your molecular concentration should be significantly below 400 nM. For a 300 bp fragment, the MW is 660*300 = 1e5 Dalton. 400 nM of your molecule will be 400e-4 g/l = 400e-10 g/ul = 40 ng/ul.
This agrees with my intuition that you should be below around 10 ng/ul, perhaps at 5 ng/ul of reaction.
#106723 Salary
Posted
Ameya P
on 13 April 2011 - 09:07 PM
So I can do nothing about it. But yes, I would like to know and learn how to negotiate salaries for my future. I cant accept (or afford) low wages throughout my life.
#106410 gelatin staining with coomassie: how do I make it work?
Posted
mascat
on 11 April 2011 - 02:46 AM
I have been trying to set up gelatin zymography in my lab and ran into a strange problem. When I previously stained gels with a really old and dark Commassie solution somebody once gave me, the gelatin inthe SDS polyacrylamide gel stained nicely, giving a dark blue background over which I could see MMP digestion bands. When I ran out of this solution, I bought Bio-Rad Biosafe Coomassie, just to find out that no matter how long I incubate the gel with it, it will stain the protein bands but it never stains the background, making it impossible to discern any digestion bands...
Any suggestion as to why this happens? Why would gelatin not be stained by this type of Coomassie?! (I use 300 bloom gelatin at a final concentration of 1 mg/ml)
I am willing to buy a different Coomassie, but which one would be best to overcome this problem?
Thanks!
#104743 How do you use tips???
Posted
Adrian K
on 25 March 2011 - 01:48 AM
#104109 Help identifying some organisms
Posted
Phil Geis
on 18 March 2011 - 03:36 PM
I am a mycologist. Suggest you isolate these fungi - it's not so easy to identify without colony morphology. That said - I think I see some Fusaria as well as what might be a dematiaceous fungus with alot of Gram negative bacteria.
#104110 Gram Positive and Gram Negative
Posted
Phil Geis
on 18 March 2011 - 03:39 PM
#103640 please correct
Posted
pito
on 15 March 2011 - 12:38 AM
claritylight, on 14 March 2011 - 02:35 PM, said:
Just tell me if the below calculations are correct and I will figure out what I want on my own and we can all move on:
If I put 10ul of the 1ug/ul DNA into a tube, add 190ul water, this = 200ul total volume, and the DNA in this tube
now has concentration of (10ul/200ul)*1000ng/ul = 50ng/ul right?
What I want to know is how much amount of DNA is in the tube. I did 50ng/ul*200ul = 10000ng = 10ug, so there's 10ug of DNA in the tube. Is that right?
Ok, now I get it, see: telling you have 10µl of a 1µg/µl stock is not the same as just saying: 10µl of 10ng...
10µl of 1µg/µl in a volume of 190µl means you have in total 10µg in 200µl thus 10µg/200µl = 1/20µl = 1000ng/20µl = 100ng/2µl = 50ng/µl.
this is what homebrew allready did.
So yes, if you have 50ng/µl and you have 200µl , yeah, you have 50*200 ng DNA= 10000ng = 10µg...
But I dont understand why you do this second calculation!
You started by saying you would add 10µl of a 1µg/µl solution in that tube... So you knew from the start it was 10µg ..
(10µl*1ng/µl = 10ng .. and no matter how much water you add, even its 19999999liter, it will still stay 10ng of DNA in the end... Its the concentration that changes, not the amount of DNA itself)
You calculate B , using A to calculate A in the end ...
But still: I have the feeling you dont understand the formula or that you dont know what you are doing.
#101329 DNA, Gel
Posted
pito
on 20 February 2011 - 11:51 AM
sxh999, on 20 February 2011 - 10:37 AM, said:
I meant I have problem to attach the image of my Gel in this website.
I will try to poster the image here, so you can have a look and help me to analyze. thank you very much.
#101258 DNA, Gel
Posted
sxh999
on 19 February 2011 - 10:26 AM
#101268 DNA, Gel
Posted
seanspotatobusiness
on 19 February 2011 - 11:56 AM
#101328 DNA, Gel
Posted
sxh999
on 20 February 2011 - 10:37 AM
I meant I have problem to attach the image of my Gel in this website.
I will try to poster the image here, so you can have a look and help me to analyze. thank you very much.
#101495 copy number of gene in genome
Posted
HomeBrew
on 22 February 2011 - 03:00 AM
So, while expression level does not change the gene's copy number, the copy number of a gene in a genome can influence the expression level -- if you have two copies of a particular gene in a genome, the expression level of that gene would be double relative to a strain which has only one copy of the gene (all other things being equal).
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