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# Convert 2gl^-1 into usable unit for use in aqueous solution?

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### #1 humphry

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Posted 07 April 2009 - 05:57 PM

Hi,

I am trying to figure out how to use 'liter^-1', as in 2 gram/liter^-1 (2 gl^-1). I know if the ratio was 2 g/l the resulting ppm would be 2000, but I do not know how to use the negative exponent. If someone could explain the process or offer an equation/formula I would be most grateful! I would like to convert the solution to g/l (or mg/l) so I can calculate the ppm.

If I calculate l^-1 I get 1000m^-3, which I do not see as being useful. I am trying to figure out how to mix two different substances: CaCl2 @ 8 g/l^-1 and alkyl polyglucoside @ 2 g/l^-1. For a donor solution (I think that is the right term?) I am going to use one liter of deionized water for mixing the CaCl2. To that mix I will add chelated Ca and chelated Mg along with phosphorus salts (anions).

P.S. This is not homework, I am in college but this is something I am working on by myself as a hobby.

Thank you for you any help

Edited by humphry, 07 April 2009 - 06:00 PM.

### #2 bob1

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Posted 07 April 2009 - 09:14 PM

The answer depends on the solvent... if it is water (1 g/cm3) then you will have 2 parts per 1000 or 2000 parts per million, however if the solvent has a density less than or greater than water the answer will be different.

With gases the problem becomes harder requiring mol fractions and molecular masses etc.

2 gram/liter^-1 (2 gl^-1)

??? use the sub and sup commands e.g. [command] text [/command] to write this properly
`gl[sup]-1[/sup]`
will give you gl-1. Besides which, grams per litre per litre as you wrote the first instance is a nonsensical unit.

### #3 humphry

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Posted 08 April 2009 - 10:44 AM

Hi,

The answer depends on the solvent... if it is water (1 g/cm3) then you will have 2 parts per 1000 or 2000 parts per million, however if the solvent has a density less than or greater than water the answer will be different.

Thanks for your response. Yes the solvent is deionized water, I mentioned that in my first post but I called it the 'donor solution' which I assume is an incorrect term? I thought maybe it should have been called 'receiver solution', thanks for clearing that up for me.

Are you saying 2 g/l-1 is the same as 2 g/l, and both equal 2000ppm? How is this so? I knew that 2 g/l was 2000ppm, but how can 2 g/l-1 be 2000ppm?

How does on calculate the weight of 2 g/l-1 (CaCl2/deionized water)? How many grams per liter does 2 gl-1 equal? My problem is I do not know how to use liter-1...

2 gram/liter^-1 (2 gl^-1)

??? use the sub and sup commands e.g. [command] text [/command] to write this properly
`gl[sup]-1[/sup]`
will give you gl-1.

The use of the carrot is correct as far as I understand, as is the use of x2. Using the carrot is more difficult to read but easier to type.

Besides which, grams per litre per litre as you wrote the first instance is a nonsensical unit.

Nowhere did I write g/l/l. I wrote "2 gram/liter^-1 (2 g/l^-1)" for the sake of clarity, which I guess I did not achieve (there is a space between the amount and the first parenthesis).

Edited by humphry, 08 April 2009 - 10:45 AM.

### #4 bob1

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Posted 08 April 2009 - 04:42 PM

I was assuming that you had made a mistake in your post and was meaning to write g/l or gl-1. Google calculator has 1 gram / (litre^(-1)) = 1.0 × 10-6 m3 kg or equivalent to 1 ml = 1 gram, or equivalent to g/l

Writing g/l is equivalent to writing gl-1, OK? Therefore, writing g/l-1 is equivalent to writing g/l/l or gl-2 in terms of mathematics, though I must be wrong there. I was assuming that you had made a mistake in your post and was meaning to write g/l or gl-1

Your use of the carrot is correct, I just thought you had confused yourself.