I take 5 ul of dNTPs (1mM stock solution) to put into a PCR reaction --> I suppose this is 0.25 mM of each dATP, dCTP, dGTP and dTTP (¿?)
PCR reaction = 50 ul
According to my calculations (C1V1=C2V2) --> C2 = [(1000 pmol/ul)(5 ul)] / 50 ul = 100 pmol/ul
That is, the concentration of dNTPs in the 50 ul PCR reaction is 100 uM. This in turn means that I have 25 uM of each individual dNTP (i.e., dATP, dCTP........dTTP) in the 50 ul PCR reaction.
Is all this correct or am I completely
I am comparing two protocols, and 25 uM of each dNTP looks a bit low.
THANKS EVERYBODY FOR YOUR HELP !!!!!!!!!!!!!! GOD BLESS YOU ALL !!!!!!













