I need a simple calculation, i.e conversion of 30% H2O2(FW 34.5) to 2mM H2O2
Is this right. molarity=%*10/FW
thanx
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#1
novagen
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Posted 28 January 2009 - 05:11 AM
Hi all,
I need a simple calculation, i.e conversion of 30% H2O2(FW 34.5) to 2mM H2O2
Is this right. molarity=%*10/FW
thanx
I need a simple calculation, i.e conversion of 30% H2O2(FW 34.5) to 2mM H2O2
Is this right. molarity=%*10/FW
thanx
Service to man is service to God
#2
T C
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Posted 28 January 2009 - 06:26 AM
Hello
Use this
Molarity= (weight in grams/FW in grams)*(1000/volume in mL)
If you % is weight/volume then you can use it directly (chk the formula you gave, I think its wrong, but not sure...too tired to chk it
), if its volume/volume then you need to get the weight by using density that will be given on the bottle.
Hope it helps.
TC
Use this
Molarity= (weight in grams/FW in grams)*(1000/volume in mL)
If you % is weight/volume then you can use it directly (chk the formula you gave, I think its wrong, but not sure...too tired to chk it
), if its volume/volume then you need to get the weight by using density that will be given on the bottle.Hope it helps.
TC
#3
Julio-Claudian
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Posted 29 January 2009 - 05:46 AM
I did the conversion for 96% sulfuric acid as follow:
(96*density*10)/FW
30% H2O2 will have a density of 1.11 and FW of 34.01 (http://www.jtbaker.c...hhtml/H4065.htm). So it'll arrive at about 9.7M. From here, it's M1V1=M2V2
(96*density*10)/FW
30% H2O2 will have a density of 1.11 and FW of 34.01 (http://www.jtbaker.c...hhtml/H4065.htm). So it'll arrive at about 9.7M. From here, it's M1V1=M2V2
#4
novagen
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Posted 29 January 2009 - 05:37 PM
Thank a lot TC anf dreamchaser
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