**Besides; Is 1ppm the same like 1mg/l ? Or does it depend in other factors like the density of the solute and solvent?**

Thanks for any inputs.

Submit your paper to J Biol Methods today!

Started by seasons, Mar 24 2005 03:59 PM

9 replies to this topic

Posted 24 March 2005 - 03:59 PM

I have to make a solution of 10,000ppm hypochlorite, since 1ppm is like 1mg/l for a solute in water solution. Does this mean that i have to add 10,000mg hypochlorite in 1liter water? If hypochlorite is in a liquid form, should i take into account its density and from that to find the volume i add to the water to get a totol of 1 litre?

** Besides; Is 1ppm the same like 1mg/l ? Or does it depend in other factors like the density of the solute and solvent? **

Thanks for any inputs.

Thanks for any inputs.

Posted 24 March 2005 - 05:30 PM

I have to make a solution of 10,000ppm hypochlorite, since 1ppm is like 1mg/l for a solute in water solution. Does this mean that i have to add 10,000mg hypochlorite in 1liter water? If hypochlorite is in a liquid form, should i take into account its density and from that to find the volume i add to the water to get a totol of 1 litre?

** Besides; Is 1ppm the same like 1mg/l ? Or does it depend in other factors like the density of the solute and solvent? **

Yes: 1 ppm is like 1 part for milion = 1 / EXP6 = 1mg/l = 1microgram/ml = ...

You have to bring 10,000mg hypochlorite to 1 liter with water. Of course you have to take into account the density.

If you let me know which hypochlorite you are using, I can calculate it for you

Yes: 1 ppm is like 1 part for milion = 1 / EXP6 = 1mg/l = 1microgram/ml = ...

You have to bring 10,000mg hypochlorite to 1 liter with water. Of course you have to take into account the density.

If you let me know which hypochlorite you are using, I can calculate it for you

Posted 24 March 2005 - 08:47 PM

I have to make a solution of 10,000ppm hypochlorite, since 1ppm is like 1mg/l for a solute in water solution. Does this mean that i have to add 10,000mg hypochlorite in 1liter water? If hypochlorite is in a liquid form, should i take into account its density and from that to find the volume i add to the water to get a totol of 1 litre?

Besides; Is 1ppm the same like 1mg/l ? Or does it depend in other factors like the density of the solute and solvent?

Yes: 1 ppm is like 1 part for milion = 1 / EXP6 = 1mg/l = 1microgram/ml = ...

You have to bring 10,000mg hypochlorite to 1 liter with water. Of course you have to take into account the density.

If you let me know which hypochlorite you are using, I can calculate it for you

Thank you very much, chantel.

The one i use is Sodium hypochlorite (NaOCl), with a stock concentration of 12% . Will you please show me how to calculate 10,000ppm hypochlorite from a 12% stock?

THanks again.

Posted 25 March 2005 - 04:02 AM

hi

12% solution means 120g/l

so l quess that you should mix 83ml of your stock solution with 917ml H2O

12% solution means 120g/l

so l quess that you should mix 83ml of your stock solution with 917ml H2O

Posted 25 March 2005 - 04:33 AM

hi

12% solution means 120g/l

so l quess that you should mix 83ml of your stock solution with 917ml H2O

Thanks, fred, but will you please show me how you think that way, because i need to know how to do it for future work.

Thanks alot.

Posted 25 March 2005 - 06:10 AM

well

12%

that says, as diluent is generally H2O, that you have in mass 12% of water mass

As 1liter weight 1000g, 12%solution is 12% of 1000.

So it's 120g.

You have then 120g of hypochlorite per liter.

after it's an ordinary way to dilute.

12%

that says, as diluent is generally H2O, that you have in mass 12% of water mass

As 1liter weight 1000g, 12%solution is 12% of 1000.

So it's 120g.

You have then 120g of hypochlorite per liter.

after it's an ordinary way to dilute.

Posted 25 March 2005 - 06:12 AM

[quote name='seasons' date='Mar 25 2005, 05:33 AM']

[quote name='fred_33' date='Mar 25 2005, 05:02 AM']will you please show me how you think that way, because i need to know how to do it for future work.[/quote]

it's not that difficult...

you need 10 000 mg in one liter and

you have 120 g per liter, which is like 120 000 mg/l

so 10 000 divided by 120 000 is 0.08333 liter which is like 83.3 ml

and now complete your volume with water up to 1000 ml (916.7)

Simon

[quote name='fred_33' date='Mar 25 2005, 05:02 AM']will you please show me how you think that way, because i need to know how to do it for future work.[/quote]

it's not that difficult...

you need 10 000 mg in one liter and

you have 120 g per liter, which is like 120 000 mg/l

so 10 000 divided by 120 000 is 0.08333 liter which is like 83.3 ml

and now complete your volume with water up to 1000 ml (916.7)

Simon

Posted 25 March 2005 - 07:03 AM

Thanks alot.

Posted 25 March 2005 - 07:15 AM

What if i use this formula:

as ppm = parts per million

and % = parts per one hundred

then 10,000 / 1,000,000 = 1/100 = 1%

It means that i only need 1% as my final concentration from my 12% stock. Is this correct?

Please, ideas. Thanks.

as ppm = parts per million

and % = parts per one hundred

then 10,000 / 1,000,000 = 1/100 = 1%

It means that i only need 1% as my final concentration from my 12% stock. Is this correct?

Please, ideas. Thanks.

Posted 31 March 2005 - 12:08 PM

What if i use this formula:

as ppm = parts per million

and % = parts per one hundred

then 10,000 / 1,000,000 = 1/100 = 1%

It means that i only need 1% as my final concentration from my 12% stock. Is this correct?

Please, ideas. Thanks.

Hi Seasons:

Simmonsays and Fred 33 are correct.

I do not think your last formula is correct.

I will try to explain in a simpler way the calculation.

You should not be confused by 10,000 ppm, this is just like 10g/l = 1%.

Your stock NaOCl is 12% = 12g/100ml = 120g/l

You have to dilute your stock 12 times. If you want to prepre 100ml of NaOCl 1% the calculation is the follow:

100ml / 12 = 8.33 ml of stock 12% diluted to 100ml

100 ml - 8.33 ml = 91.67 ml of water to add.

8.33 ml stock 12% + 91.67 ml of water = 1% solution = 10,000 ppm

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