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w/v calculation

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#1 heathenbrewing



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Posted 27 March 2018 - 07:01 PM

I apologize if this is a elementary question as I do not have a background in science, only seeking to increase my understanding of the discipline.
A media recipe calls for 0.04 g/L CaCl2 2H2O. In order to minimize variance from liter to liter I would favor creating a stock solution as opposed to weighing the dry component for each L made. My goal being the addition of 1mL of the concentrate to 999mL of the media would result in the desired concentration.
If I am understanding the mathematics correctly I should create a 1000X CaCl2 2H2O solution by adding 40g/L. Wikipedia claims this concentration of dihydrate should be soluble in ddH2O.
1mL of 40g/L divided by 1000 = 0.04g/L. Is that correct? If not, where did I error?
Thanks in advance.

#2 bob1


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Posted 28 March 2018 - 06:02 AM

Your calculations look correct.


The equation you want is:


C1V1 = C2V2


Where C1 and V1 are your starting concentrations and C2 and V2 are your final concentrations.


C1 = 40 g/L, V1 = ?, C2 = 0.04 g/L, V2 = 1 L


rearrange to get V1 by itself 0.04*1/40 = 0.001 L or 1 ml.

#3 heathenbrewing



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Posted 05 April 2018 - 04:31 PM

Thank you for response. I will learn more of the C1V1 calculations but your explanation makes it pretty clear.

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