Hi

Could any one help with this query. I would like to calculate the concentration that I used from a pure chemical Methyl laurate. The purity is 98%. MW is 214.34. I took directly 200, 100 and 50 microlitres for my experiment. Just wondering, how do I express this in concentration? such as in Molarity or in Micrograms/ml

# Calculating concentration

### #1

Posted 03 August 2014 - 07:03 AM

### #2

Posted 03 August 2014 - 08:44 AM

what is the density of the compound (required to determine mass and moles of compound added) ?

final volume (required to determine concentration)?

genius does what it must

i do what i get paid to do

### #3

Posted 03 August 2014 - 10:07 AM

Thank you. The density is 0.87 g/mL. The final volume I took for my experiment is 200, 100 and 50 microlitres (directly from the pure synthetic bottle for my experiment). However, I need to write it as final concentration, not as volume.

Is this correct way I am doing: 0.87g/ml = 870g/L = 870*98/100 = 852.6 g = 852.6/214.34 = 3.97 mol/L. So in 100 microlitres it is 0.397 and in 50 microlitres it is 0.19 M? Am I right? Thank you

**Edited by chandch, 03 August 2014 - 11:02 AM.**

### #4

Posted 03 August 2014 - 12:06 PM

I think this is correct up to your 3.97 mol/L result. I can make no sense of the next statement. The molarity of any amount of your chemical is unchanged. If you mix that amount into a larger volume, the molarity of the final solution will change, but to know the new molarity, you need to know the amount of volume you are diluting into.

I can't even figure out how you got the .397 M result.

### #5

Posted 03 August 2014 - 10:21 PM

reading your posts it seems you simple took 200 microliter , 100microliter and 50 microliter from the solution and thats it.

You need to tell in how much you diluted it? Was the end volume 200 microliter each time?

If you don't know it, then ask it! Better to ask and look foolish to some than not ask and stay stupid.

### #6

Posted 04 August 2014 - 02:33 AM

Thank you. phage434 and Pito. I simply took 200, 100 and 50 microlitres and used directly for my experiment (3 different volumes of same pure compound, but I would like to express as concentration). I did not diluted it. Coming to my calculation if it is 3.97 mol/L, then can it be a 0.397 M in 100 microlitres? I am not sure, if I calculated it right. I calculated based on : 3.97 mol in 1 Litre. So 1 litre = 1000 ml. So in 100microlitres it is 0.0397 M . Am I right now?

### #7

Posted 04 August 2014 - 02:44 AM

Thank you. phage434 and Pito. I simply took 200, 100 and 50 microlitres and used directly for my experiment (3 different volumes of same pure compound, but I would like to express as concentration). I did not diluted it. Coming to my calculation if it is 3.97 mol/L, then can it be a 0.397 M in 100 microlitres? I am not sure, if I calculated it right. I calculated based on : 3.97 mol in 1 Litre. So 1 litre = 1000 ml. So in 100microlitres it is 0.0397 M . Am I right now?

But the concentration is the same than!

If you did not dilute it you would just have added the same concentration to your sample...

The sample itself of course would have an effect on the end concentration.

I will give you a simple example:

if you have 10 moles per liter for a certain solution than this concentration does not change whether you have taken 100 microliter or 50 microliter.

The concentration is the same!

The amount of moles is different of course: for 100 microliter you have twice the amount as for 50 microliter.

1 liter = 10 moles

100 microliter = 0,1 ml = 0,1ml x 10^-3 liter , this meaning 10/10 000 moles!

50 microliter is than the half of 10/10 000 moles..

Now the end concentration of course depends on to what you add this 100 microliter or 50 microliter.

If you don't know it, then ask it! Better to ask and look foolish to some than not ask and stay stupid.

### #8

Posted 04 August 2014 - 02:53 AM

Thank you. phage434 and Pito. I simply took 200, 100 and 50 microlitres and used directly for my experiment (3 different volumes of same pure compound, but I would like to express as concentration). I did not diluted it. Coming to my calculation if it is 3.97 mol/L, then can it be a 0.397 M in 100 microlitres? I am not sure, if I calculated it right. I calculated based on : 3.97 mol in 1 Litre. So 1 litre = 1000 ml. So in 100microlitres it is 0.0397 M . Am I right now?

But the concentration is the same than!

If you did not dilute it you would just have added the same concentration to your sample...

The sample itself of course would have an effect on the end concentration.

I will give you a simple example:

if you have 10 moles per liter for a certain solution than this concentration does not change whether you have taken 100 microliter or 50 microliter.

The concentration is the same!

The amount of moles is different of course: for 100 microliter you have twice the amount as for 50 microliter.

1 liter = 10 moles

100 microliter = 0,1 ml = 0,1ml x 10^-3 liter , this meaning 10/10 000 moles!

50 microliter is than the half of 10/10 000 moles..

Now the end concentration of course depends on to what you add this 100 microliter or 50 microliter.

Thank you. The result of my experiment is like this, as the volume increases from 50 to 200, the results were better. I did not get good results when I used 50 microlitre. Does this mean concentration has an effect on my sample? So you are saying, even though the volume increases, concentration remain same? Am I right? Do I need say as the volume increases the results were better, (instead of saying as concentration increases the results were better)?

**Edited by chandch, 04 August 2014 - 02:53 AM.**

### #9

Posted 04 August 2014 - 03:18 AM

But the concentration is the same than!

If you did not dilute it you would just have added the same concentration to your sample...

The sample itself of course would have an effect on the end concentration.

I will give you a simple example:

if you have 10 moles per liter for a certain solution than this concentration does not change whether you have taken 100 microliter or 50 microliter.

The concentration is the same!

The amount of moles is different of course: for 100 microliter you have twice the amount as for 50 microliter.

1 liter = 10 moles

100 microliter = 0,1 ml = 0,1ml x 10^-3 liter , this meaning 10/10 000 moles!

50 microliter is than the half of 10/10 000 moles..

Now the end concentration of course depends on to what you add this 100 microliter or 50 microliter.

Thank you. The result of my experiment is like this, as the volume increases from 50 to 200, the results were better. I did not get good results when I used 50 microlitre. Does this mean concentration has an effect on my sample? So you are saying, even though the volume increases, concentration remain same? Am I right? Do I need say as the volume increases the results were better, (instead of saying as concentration increases the results were better)?

But what did you do with the "volumes" ?

Did you add the 200 microliter to something else?

The concentration stays the same! In the 200 microliter , 50 microliter and 100 microliter the concentration is the same!

The total amount of your substance is different of course..... because 200 microliter has more moles in it than 50 microliter!

If you don't know it, then ask it! Better to ask and look foolish to some than not ask and stay stupid.

### #10

Posted 04 August 2014 - 03:35 AM

But the concentration is the same than!

If you did not dilute it you would just have added the same concentration to your sample...

The sample itself of course would have an effect on the end concentration.

I will give you a simple example:

The concentration is the same!

1 liter = 10 moles

100 microliter = 0,1 ml = 0,1ml x 10^-3 liter , this meaning 10/10 000 moles!

50 microliter is than the half of 10/10 000 moles..

Now the end concentration of course depends on to what you add this 100 microliter or 50 microliter.

Thank you. The result of my experiment is like this, as the volume increases from 50 to 200, the results were better. I did not get good results when I used 50 microlitre. Does this mean concentration has an effect on my sample? So you are saying, even though the volume increases, concentration remain same? Am I right? Do I need say as the volume increases the results were better, (instead of saying as concentration increases the results were better)?

But what did you do with the "volumes" ?

Did you add the 200 microliter to something else?

The concentration stays the same! In the 200 microliter , 50 microliter and 100 microliter the concentration is the same!

The total amount of your substance is different of course..... because 200 microliter has more moles in it than 50 microliter!

Sorry I am totally confused with the term concentration and amount. I did not diluted 200 microlitres. I know, you understood my point. But I am confused. I am working on fungal inhibition with a pure chemical compounds described above. I took 3 volumes and tested on fungal inhibition. When I used 200 microlitre the inhibition was higher, but could not see inhibition at 50 microlitre. So If I understood correctly, I used only one concentration (is conc expressed in %?) or (I think concentration is expressed in moles, millimoles, micromoles - if I dilute from 1 mole to 1milli mole, the concentration usually decreases because of dilution?). So in my experiment, is the quantity/amount or concentration (do not know the right term here to be used) have an effect on fungal growth. Also in one paper, authors used 1 ng 1 μg 1 mg. They also found good results at higher 1 mg. But they said concentration? Is this right term or do they have say quantity/amount.

If you are saying 200 microliters has more moles than in 50 microlitre (Is this not a concentration?). Then in my calculation described above 3.97 mol in 1 Litre. So 1 litre = 1000 ml. So in 100microlitres it is 0.0397 M . So 100 microlitres has less moles?

Thank you and Sorry

### #11

Posted 04 August 2014 - 03:43 AM

But the concentration is the same than!

If you did not dilute it you would just have added the same concentration to your sample...

The sample itself of course would have an effect on the end concentration.

I will give you a simple example:

The concentration is the same!

1 liter = 10 moles

100 microliter = 0,1 ml = 0,1ml x 10^-3 liter , this meaning 10/10 000 moles!

50 microliter is than the half of 10/10 000 moles..

Now the end concentration of course depends on to what you add this 100 microliter or 50 microliter.

But what did you do with the "volumes" ?

Did you add the 200 microliter to something else?

The concentration stays the same! In the 200 microliter , 50 microliter and 100 microliter the concentration is the same!

The total amount of your substance is different of course..... because 200 microliter has more moles in it than 50 microliter!

Sorry I am totally confused with the term concentration and amount. I did not diluted 200 microlitres. I know, you understood my point. But I am confused. I am working on fungal inhibition with a pure chemical compounds described above. I took 3 volumes and tested on fungal inhibition. When I used 200 microlitre the inhibition was higher, but could not see inhibition at 50 microlitre. So If I understood correctly, I used only one concentration (is conc expressed in %?) or (I think concentration is expressed in moles, millimoles, micromoles - if I dilute from 1 mole to 1milli mole, the concentration usually decreases because of dilution?). So in my experiment, is the quantity/amount or concentration (do not know the right term here to be used) have an effect on fungal growth. Also in one paper, authors used 1 ng 1 μg 1 mg. They also found good results at higher 1 mg. But they said concentration? Is this right term or do they have say quantity/amount.

If you are saying 200 microliters has more moles than in 50 microlitre (Is this not a concentration?). Then in my calculation described above 3.97 mol in 1 Litre. So 1 litre = 1000 ml. So in 100microlitres it is 0.0397 M . So 100 microlitres has less moles?

Thank you and Sorry

Concentration = a certain amount per volume. Meaning: X mg per X ml (or grams per liter , or nano grams per microliter or mg per liter...) or moles/ liter (this is than the molar concentration.

Amount = total number of a certain component...; for example: 10 grams or 1 kilogram or .... (or could also be expressed as a volume).

for you its like this:

200 microliter of a certain concentration added to a sample

100 microliter ....

50 microliter...

The concentration of those 3 volumes is the same!

The amount however is different! 200 microliter holds more of the component than the 50 microliter.

But what did you do ? I still do not understand it.

You added to fungal (spores) to the 200 microliter?

About that paper: the amounts they describe are (I think) the total amount of that drug: meaning they added 1 ng , 1 microgram or 1 mg in total to a certain fixed volume... but I do not know this without the correct information.

Another oversimplified example:

component Y has a molar concentration of 8 moles/liter.

If I take 1 liter I have 8 moles.

If I take 0,5 liter I have 4 moles.

The concentration of the 1 liter and 0,5 liter is however the same:

1 liter = 8 moles, 8moles/1liter = 8moles per liter

0,5 liter = 4 moles , 4moles/0,4liter = 8 moles per liter

The total amount of moles is however different: 1 liter contains 8 moles , 0,5 liter is only 4 moles...

### #12

Posted 04 August 2014 - 03:45 AM

If you are saying 200 microliters has more moles than in 50 microlitre (Is this not a concentration?). Then in my calculation described above 3.97 mol in 1 Litre. So 1 litre = 1000 ml. So in 100microlitres it is 0.0397 M . So 100 microlitres has less moles?

Thank you and Sorry

Yes, 200 microliter has more moles than 50, but the concentration is the same!

3,97 moles in 1 liter , 1 liter = 1000 ml , so 1000 ml will have 3,97 moles.

1 ml will have 3,97/1000 moles!

100 microliter will have 3,97/10000 moles!

However the molar concentration (M) is the same for all!

moles =/= M !

M = moles per liter! Its a concentration.

### #13

Posted 04 August 2014 - 03:52 AM

But the concentration is the same than!

If you did not dilute it you would just have added the same concentration to your sample...

The sample itself of course would have an effect on the end concentration.

I will give you a simple example:

The concentration is the same!

1 liter = 10 moles

100 microliter = 0,1 ml = 0,1ml x 10^-3 liter , this meaning 10/10 000 moles!

50 microliter is than the half of 10/10 000 moles..

Now the end concentration of course depends on to what you add this 100 microliter or 50 microliter.

But what did you do with the "volumes" ?

Did you add the 200 microliter to something else?

Sorry I am totally confused with the term concentration and amount. I did not diluted 200 microlitres. I know, you understood my point. But I am confused. I am working on fungal inhibition with a pure chemical compounds described above. I took 3 volumes and tested on fungal inhibition. When I used 200 microlitre the inhibition was higher, but could not see inhibition at 50 microlitre. So If I understood correctly, I used only one concentration (is conc expressed in %?) or (I think concentration is expressed in moles, millimoles, micromoles - if I dilute from 1 mole to 1milli mole, the concentration usually decreases because of dilution?). So in my experiment, is the quantity/amount or concentration (do not know the right term here to be used) have an effect on fungal growth. Also in one paper, authors used 1 ng 1 μg 1 mg. They also found good results at higher 1 mg. But they said concentration? Is this right term or do they have say quantity/amount.

Thank you and Sorry

Concentration = a certain amount per volume. Meaning: X mg per X ml (or grams per liter , or nano grams per microliter or mg per liter...) or moles/ liter (this is than the molar concentration.

Amount = total number of a certain component...; for example: 10 grams or 1 kilogram or .... (or could also be expressed as a volume).

for you its like this:

200 microliter of a certain concentration added to a sample

100 microliter ....

50 microliter...

The concentration of those 3 volumes is the same!

The amount however is different! 200 microliter holds more of the component than the 50 microliter.

But what did you do ? I still do not understand it.

You added to fungal (spores) to the 200 microliter?

About that paper: the amounts they describe are (I think) the total amount of that drug: meaning they added 1 ng , 1 microgram or 1 mg in total to a certain fixed volume... but I do not know this without the correct information.

Another oversimplified example:

component Y has a molar concentration of 8 moles/liter.

If I take 1 liter I have 8 moles.

If I take 0,5 liter I have 4 moles.

The concentration of the 1 liter and 0,5 liter is however the same:

1 liter = 8 moles, 8moles/1liter = 8moles per liter

0,5 liter = 4 moles , 4moles/0,4liter = 8 moles per liter

The total amount of moles is however different: 1 liter contains 8 moles , 0,5 liter is only 4 moles...

Thank you. I understan

Thank you and Sorry

Yes, 200 microliter has more moles than 50, but the concentration is the same!

3,97 moles in 1 liter , 1 liter = 1000 ml , so 1000 ml will have 3,97 moles.

1 ml will have 3,97/1000 moles!

100 microliter will have 3,97/10000 moles!

However the molar concentration (M) is the same for all!

moles =/= M !

M = moles per liter! Its a concentration.

Thank you. I put that chemical on filter paper and exposed to fungi (with out direct contact). I understood you point now. The molar concentration is same for all 3 volumes (The molar concentration will only decrease when you diluted). Here in my experiment the volume concentration has an effect on fungi, which means there is more compound in 200 microlitres than in 100 microlitres? Am I right now

### #14

Posted 04 August 2014 - 04:27 AM

yes, you are correct now.

out of curiosity, did you control the spread of the compound on the filter paper? or did you just allow the compound to spread as far as the volume took it?

**Edited by mdfenko, 04 August 2014 - 04:29 AM.**

genius does what it must

i do what i get paid to do

### #15

Posted 04 August 2014 - 04:47 AM

yes, you are correct now.

out of curiosity, did you control the spread of the compound on the filter paper? or did you just allow the compound to spread as far as the volume took it?

Thank you. we used split petri dishes. In the control plate, one side of the petri plate is placed with plug of fungi. As soon it reaches the partition of the plate, we took readings.