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dilution question


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#1 uzalive

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Posted 29 August 2013 - 12:38 PM

You are provided with an antibody solution (Ab) that has a concentration of 600 microgram/microlitre

 

For lab, it is necessary make the following dilution.

 

5ul of 1:60 Ab + 5ul of buffer to make a __________ dilution at ________ ug/ul.

 

 

Can someone help in solving this problem.  It seems that I am missing some basic concept.  I get the ug/ul, but I don't get the dilution.

Please explain in detail. 



#2 Tabaluga

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Posted 29 August 2013 - 02:02 PM

You make a 1:60 dilution of the Ab. That means, if your starting concentration was 600 ug/ul, you will get a concentration of 1:60 * 600 = 10 ug/ul.

Now you take 5 ul of that, which is 5 * 10 ug = 50 ug. And in which volume do we have these 50 ug when we add 5 ul buffer to the whole thing ? 5ul+5ul = 10 ul, so you have 50 ug in 10 ul volume.

So your concentration is 5 ug/ul now.

Compared to the initial Ab concentration, its 5/600 = 1:120 dilution.


Edited by Tabaluga, 29 August 2013 - 04:34 PM.

Il dort. Quoique le sort fût pour lui bien étrange,
Il vivait. Il mourut quand il n'eut plus son ange;
La chose simplement d'elle-même arriva,
Comme la nuit se fait lorsque le jour s'en va.

 


#3 mdfenko

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Posted 29 August 2013 - 03:43 PM

Compared to the initial Ab concentration, its 5/600 = 1:125 dilution.

watch your math, 5/600=120 (2x diluted from 1:60)


Edited by mdfenko, 29 August 2013 - 03:44 PM.

talent does what it can
genius does what it must
i do what i get paid to do

#4 Tabaluga

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Posted 29 August 2013 - 04:36 PM

Ooops, you're right of course. Edited it in my post.


Il dort. Quoique le sort fût pour lui bien étrange,
Il vivait. Il mourut quand il n'eut plus son ange;
La chose simplement d'elle-même arriva,
Comme la nuit se fait lorsque le jour s'en va.

 





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