Posted 02 June 2013 - 05:57 AM
I have stock solution of
2) NAD+ (2mM)
3) PGM (1.2U/mL)
4) G6PDH (2U/mL)
I will need a final volume of 200ul with the following:
2) NAD+ (1mM)
3) PGM (0.6U/mL)
4) G6PDH (1U/mL)
Can anyone give hints/formula on how to do the calculation? Many thanks!
Posted 02 June 2013 - 06:15 AM
You can use M1V1 = M2V2 to calculate the amount of volume required to make your solution with desired concentration and volume. For example:
M is moles per litre or the concentration; V is the volume of solution in litre. So, M1 is the concentration of your stock solution; V1 is the volume of your stock solution; M2 is the concentration of solution you want; V2 is the final volume you need.
In order to make 200 uL of 0.5mM DTT from 1mM DDT, you will need:
M1V1 = M2V2
(1mM)(x) = (0.5mM)(200 uL)
x = 100 uL
It means you'll need 100 uL of 1mM DDT in 100 uL of water/ solvent you used to dissolve the DDT powder. So 100 uL of stock solution and 100 uL of water/ solvent will make a total of 200 uL.
Likewise, the rest of the solutions can be calculated using the same formula. Hope this helps...=)
Posted 03 June 2013 - 05:28 AM
if 4 solutions then just dilute each one with an equal volume of diluent.
if one solution with 4 components then you can't do it with the stocks that you have.
genius does what it must
i do what i get paid to do
Posted 03 June 2013 - 06:42 AM
I need to make one solution with the 4 components.
Is your stock solution a mix of the 4 components at the concentrations stated? In which case you just need to do a 2-fold dilution for your final concentrations.
Or do you have 4 stock solutions (one for each component)? In which case, as Mdfenko said, what you want to do is impossible.