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# help

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### #1 pipo88

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Posted 11 February 2013 - 03:40 AM

Hello.
I have a solution of SBS (sodium bisulphite) 40 % w/w, 1000 L. I want to make this 1.3 % so i can preserve some membranes. i need to dilute this in a tank of 65 000 L of water. What can i do?

### #2 mdfenko

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Posted 11 February 2013 - 06:30 AM

you can't make 65 000 L with 1000 L of 40%. 40% is ~30x 1.3%, you can only make ~ 30 000 L (do you really mean L? that's a lot of solution).
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### #3 pipo88

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Posted 12 February 2013 - 03:32 AM

yes, is 65000 liter tank. If i need more than 1000L of SBS i can get. The point is what calculations i need to make to estimate how much i need to achieve the concentration of 1.3 %.

### #4 casandra

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Posted 12 February 2013 - 10:39 AM

pipo88, on 12 February 2013 - 03:32 AM, said:

yes, is 65000 liter tank. If i need more than 1000L of SBS i can get. The point is what calculations i need to make to estimate how much i need to achieve the concentration of 1.3 %.
how about using maths rule of three or cross-multiplication......C1V1=C2V2    would work too.....
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### #5 mdfenko

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Posted 12 February 2013 - 11:44 AM

casandra is correct (i was going to tell you the same but she beat me to it).

c1=40%, c2=1.3%, v2=65 000 L. calculate for v1(the amount of 40% you need to make 65 000 L of 1.3%)

v1=(c2v2)/c1=(1.3*65000)/40=2112.5 L
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### #6 pipo88

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Posted 13 February 2013 - 01:54 AM

i thought of this. but the density of the solution is different from the water. Doesn't  the density play a part in this?

### #7 mdfenko

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Posted 13 February 2013 - 04:55 AM

pipo88, on 13 February 2013 - 01:54 AM, said:

i thought of this. but the density of the solution is different from the water. Doesn't  the density play a part in this?
no, not for this case. it is a simple dilution. try not to overthink the problem.
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