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Making a standard curve from bacterial suspensions

qPCR DNA extaction

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#1 firefly2280

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Posted 19 January 2013 - 10:37 AM

Hi

Sorry if this is an obvious question but Ive just been confusing myself!

I want to make a standard curve for S. aureus to run on my qPCR. I have bacterial suspensions - say 10^8 / ml.

If I just do a bead-beat and lyse the cells, proteinase K treat then etc, then I have a suspension that I can say is 10^8.

But then if I add 10ul to a qPCR, im only actually adding 10^6 gene copies, right? So if I want to do it this way, I need to start at a much higher dilution?

Is this right or am I totally off the mark?

Then, if I get 10ul of sample come up at 10^6, does that mean I have 10^6 in my 10ul of sample!?

thanks so much

#2 pito

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Posted 19 January 2013 - 11:13 AM

I dont really understand your question/problem.

If you have a 10^8cells/ml suspension and you use 10µl of that, then you have 10^6 cells in total (in your 10µl).
If you add this to your PCR then you would indeed have 10^6 gene copies (accepting the fact that you only have 1 copy of that gene per genome/bacterium, which I dont know).
Also: you have 10^6 bacteria in your 10µl, but  you will not be able to recuperate 100% of the DNA anyway... so you will not have 10^6 gene copies anyway...


So what is your problem? You want 10^8 copies of your gene?
If you don't know it, then ask it! Better to ask and look foolish to some then not ask and stay stupid.





Also tagged with one or more of these keywords: qPCR, DNA extaction

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