Molar CalculationMolar calculation
Posted 19 November 2012 - 11:15 AM
Can anybody show how to do the math for making a 100mM, 100uL solution of X from the commercial available X solution of 96% ?
The details of the X are as follows.
density 0.879 g/ml
i.e. How much of commercially available X to be added ?
Posted 19 November 2012 - 11:47 AM
Because you need 100µl, you need not 0,1 mol (thats for 1liter) but 0,1x10^-4 mol or 1x10^-5 mol
Since you have 223,37gram per mol, you need not 223,37 grams but 223,37 x 10^-5 grams.
and the solution s 96%, so 223,37grams is only 96%, so 100% = ? grams..
If you know this, you know how much ml you need to take from the stock.
Redo the math, check it yourself.
(its possible I made an error somewhere, buts its basic math)
Do you understand it?
Edited by pito, 19 November 2012 - 11:48 AM.
If you don't know it, then ask it! Better to ask and look foolish to some than not ask and stay stupid.