Jump to content

  • Log in with Facebook Log in with Twitter Log in with Windows Live Log In with Google      Sign In   
  • Create Account

Submit your paper to J Biol Methods today!
Photo
- - - - -

Molar Calculation

Molar calculation

  • Please log in to reply
1 reply to this topic

#1 uday

uday

    member

  • Active Members
  • Pip
  • 22 posts
0
Neutral

Posted 19 November 2012 - 11:15 AM

What a shame ! I got stuck in molar calculations.

Can anybody show how to do the math for making a 100mM, 100uL solution of X from the commercial available X solution of 96% ?

The details of the X are as follows.
96% assay
MW 222.37g/mol
density 0.879 g/ml

i.e. How much of commercially available X to be added ?

#2 pito

pito

    Veteran

  • Global Moderators
  • PipPipPipPipPipPipPipPipPipPip
  • 1,317 posts
80
Excellent

Posted 19 November 2012 - 11:47 AM

100mM= 0,1M meaning: 0,1mol per liter.
Because you need 100µl, you need not 0,1 mol (thats for 1liter) but 0,1x10^-4 mol or 1x10^-5 mol

Since you have 223,37gram per mol, you need not 223,37 grams but 223,37 x 10^-5 grams.

and the solution s 96%, so 223,37grams is only 96%, so 100% = ? grams..
If you know this, you know how much ml you need to take from the stock.



Redo the math, check it yourself.
(its possible I made an error somewhere, buts its basic math)
Do you understand it?

Edited by pito, 19 November 2012 - 11:48 AM.

If you don't know it, then ask it! Better to ask and look foolish to some than not ask and stay stupid.





Home - About - Terms of Service - Privacy - Contact Us

©1999-2013 Protocol Online, All rights reserved.