Jump to content

  • Log in with Facebook Log in with Twitter Log in with Windows Live Log In with Google      Sign In   
  • Create Account

Submit your paper to J Biol Methods today!
Photo
- - - - -

Dilution question


  • Please log in to reply
4 replies to this topic

#1 LanMolecular

LanMolecular

    member

  • Active Members
  • Pip
  • 5 posts
0
Neutral

Posted 18 March 2012 - 06:43 AM

In the experiment below, you have a protein solution (a stock solution) at 2 mg/ml. You need to make the following levels: 400 μg /ml, 100 μg /ml, 20 μg /ml, 5 μg /ml and 1 μg /ml. You need 50 ml of each concentration.

We need to find dilution, volume stock and volume buffer.
(2 mg/mL= 2000 μg /ml)

My answers;

For 400 μg /ml, dilution= 1:5, vol stock= 10 mL, vol buffer= 40 mL

For 100 μg /ml, dilution= 6:25, vol stock= 12 mL, vol buffer= 38 mL

For 20 μg /ml, dilution= 1:5, vol stock= 13 mL, vol buffer= 52 mL

For 5 μg /ml, dilution= 1:20, vol stock= 2.5 mL, vol buffer= 47.5 mL

For 1 μg /ml, dilution= 1:50, vol stock= 0.5 mL, vol buffer= 49.5 mL

Are they correct or false? Someone can teach me?

#2 bob1

bob1

    Thelymitra pulchella

  • Global Moderators
  • PipPipPipPipPipPipPipPipPipPip
  • 5,513 posts
371
Excellent

Posted 18 March 2012 - 06:05 PM

If you use the formula C1V1=C2V2, where C and V are concentration and volume, and 1 and 2 are initial and final respectively, you can work out dilution.

so for 400 ug/ml, you have 2000 (c1) x V1 = 400 (C2) x 50 (V2).
therefore V1 = 400 x50/2000
V1=10 ml, + 40 ml buffer to make 50.

I don't see how you got the rest, unless you were making some sort of serial dilution...

#3 LanMolecular

LanMolecular

    member

  • Active Members
  • Pip
  • 5 posts
0
Neutral

Posted 18 March 2012 - 11:28 PM

I think i got the answer...

Bob1's answer is another method...

What about this?

Question for 400 μg /ml,

Initial concentration : stock concentration;
400:2000 = 1:5 = 1/5 x final volume = 1/5 x 50
= 10 mL (volume stock)

Hence, dilution = 1:5, volume stock = 10 mL, volume buffer = (50 - 10)
= 40 mL

This method is applied to find all the final concentration...

Is my method acceptable?

#4 leelee

leelee

    Veteran

  • Active Members
  • PipPipPipPipPipPipPipPipPipPip
  • 652 posts
52
Excellent

Posted 19 March 2012 - 06:18 PM

All of them are incorrect, except for the first one. Assuming that you are using the original stock (2mg/ml) for all of the dilutions.

For example, in the second one, you've said you are going to add 12 ml of the stock to 38 ml of buffer.
12 x 2000ug/ml (stock conc.)= 24000ug
24000ug in your 50ml final volume (12+38)= 480ug/ml

It does kind of appear that you are doing some kind of dilution series though, but without knowing which "stock" you use for each of the subsequent dilutions, we can't tell you if you are right or not.

Your method is probably ok, but I would suggest getting used to using the standard C1V1 = C2V2 method as not all dilutions you do in the future will be as simple as the one you have given us here. :)

#5 CAT

CAT

    member

  • Active Members
  • Pip
  • 24 posts
0
Neutral

Posted 20 March 2012 - 10:18 AM

Me too. Except for 400ug/mL, I don't think the others are right. I tried to check your answer assuming you directly dilute from 2mg/mL or serial dilutions. Neither one works out. You have to give out your definition for "stock". Posted Image




Home - About - Terms of Service - Privacy - Contact Us

©1999-2013 Protocol Online, All rights reserved.