Jump to content

  • Log in with Facebook Log in with Twitter Log in with Windows Live Log In with Google      Sign In   
  • Create Account

Submit your paper to J Biol Methods today!
Photo
- - - - -

efficiency calculation from non-10 fold dilutions

qPCR efficiency

  • Please log in to reply
1 reply to this topic

#1 blue800

blue800

    member

  • Members
  • Pip
  • 4 posts
0
Neutral

Posted 14 October 2011 - 09:09 AM

I have done a 5 fold dilution series with 6 points because my genes of interest are relatively low copy number and I wanted to get enough points in my dilution series to feel confident using these primers.

I am not clear how to calculate the efficiency from log base 5. My R2 values are nearly perfect (better than .998) and my slopes are around 1.4.

I thought I should use this calculation 5^(-1/m)...but the numbers I get don't seem right.

if E=10^(-1/m), how does this change for non-10 fold dilution series?

Thanks

#2 blue800

blue800

    member

  • Members
  • Pip
  • 4 posts
0
Neutral

Posted 14 October 2011 - 09:57 AM

FWIW, I think my efficiencies are way off...or I'm calculating my slope wrong. My slope should be close to x where 2^x=5 or 2.322. which 5^(-1//2.322) = 2. So nevermind.




Home - About - Terms of Service - Privacy - Contact Us

©1999-2013 Protocol Online, All rights reserved.