I have done a 5 fold dilution series with 6 points because my genes of interest are relatively low copy number and I wanted to get enough points in my dilution series to feel confident using these primers.
I am not clear how to calculate the efficiency from log base 5. My R2 values are nearly perfect (better than .998) and my slopes are around 1.4.
I thought I should use this calculation 5^(-1/m)...but the numbers I get don't seem right.
if E=10^(-1/m), how does this change for non-10 fold dilution series?
efficiency calculation from non-10 fold dilutionsqPCR efficiency
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