# Convert 2gl^-1 into usable unit for use in aqueous solution? - Re: CaCl2 and alkyl polyglucoside (Apr/07/2009 )

Hi,

I am trying to figure out how to use 'liter^-1', as in 2 gram/liter^-1 (2 gl^-1). I know if the ratio was 2 g/l the resulting ppm would be 2000, but I do not know how to use the negative exponent. If someone could explain the process or offer an equation/formula I would be most grateful! I would like to convert the solution to g/l (or mg/l) so I can calculate the ppm.

If I calculate l^-1 I get 1000m^-3, which I do not see as being useful. I am trying to figure out how to mix two different substances: CaCl2 @ 8 g/l^-1 and alkyl polyglucoside @ 2 g/l^-1. For a donor solution (I think that is the right term?) I am going to use one liter of deionized water for mixing the CaCl2. To that mix I will add chelated Ca and chelated Mg along with phosphorus salts (anions).

P.S. This is not homework, I am in college but this is something I am working on by myself as a hobby.

Thank you for you any help

The answer depends on the solvent... if it is water (1 g/cm^{3}) then you will have 2 parts per 1000 or 2000 parts per million, however if the solvent has a density less than or greater than water the answer will be different.

With gases the problem becomes harder requiring mol fractions and molecular masses etc.

`gl[sup]-1[/sup]`

will give you gl^{-1}. Besides which, grams per litre per litre as you wrote the first instance is a nonsensical unit.

Hi,

bob1 on Apr 8 2009, 02:14 AM said:

^{3}) then you will have 2 parts per 1000 or 2000 parts per million, however if the solvent has a density less than or greater than water the answer will be different.

Thanks for your response. Yes the solvent is deionized water, I mentioned that in my first post but I called it the 'donor solution' which I assume is an incorrect term? I thought maybe it should have been called 'receiver solution', thanks for clearing that up for me.

Are you saying 2 g/l

^{-1}is the same as 2 g/l, and both equal 2000ppm? How is this so? I knew that 2 g/l was 2000ppm, but how can 2 g/l

^{-1}be 2000ppm?

How does on calculate the weight of 2 g/l

^{-1}(CaCl2/deionized water)? How many grams per liter does 2 gl

^{-1}equal? My problem is I do not know how to use liter

^{-1}...

2 gram/liter^-1 (2 gl^-1)